(2r+3)\Xb2+(R+4)\Xb2=10equadratic Equation In The Form Ax\Xb2+Bx+C

(2r+3)²+(r+4)²=10equadratic equation in the form ax²+bx+c

Answer:

5r²+20r+15=0

Step-by-step explanation:

(2r+3)²+(r+4)²=10

(4r²+12r+9)+(r+4)²=10

(4r²+12r+9)+(r²+8r+16)=10

5r²+20r+25=10

5r²+20r+15=0


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