(2r+3)\Xb2+(R+4)\Xb2=10equadratic Equation In The Form Ax\Xb2+Bx+C
(2r+3)²+(r+4)²=10equadratic equation in the form ax²+bx+c
Answer:
5r²+20r+15=0
Step-by-step explanation:
(2r+3)²+(r+4)²=10
(4r²+12r+9)+(r+4)²=10
(4r²+12r+9)+(r²+8r+16)=10
5r²+20r+25=10
5r²+20r+15=0
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